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gap junction and coupled resistance

Posted: Thu Jul 19, 2007 9:37 am
by thats_karlo
Hello,

I am wondering, can we use gap junction insted of coupled resistance between to section?

for example, consider to section A and B with a couple resistsnce

(A)-/\/\/\/\/\/\-(B)

1-Dose the following code, is a correct way to represent the above figure?
dose it need some correction?

Code: Select all


create A, B
forall nseg=1
A{\\geometry +biophysics}
B{\\geometry +biophysics}

objref RG
RG= new gap()

A RG[0].loc(0.9999)
B RG[1].loc(0.0001)
setpointer RG[0].vgap, B.v(0.0001)
setpointer RG[1].vgap, A.v(0.9999)

RG.r=0.1

2-Is ti right: if A{r1=ri(0.9)} ,B{r2=ri(0.1)}, then

axial resistance between A, B =r1+r2+RG.r

3- can we make a cell with two compartment, AND a copuling resistance in GUI tool\cell builder?


Yours,


karlo

Posted: Thu Jul 19, 2007 10:46 am
by ted
For an example of how to connect cells with gap junctions, see
Migliore M, Hines ML, Shepherd GM (2005)
The role of distal dendritic gap junctions in synchronization of mitral cell axonal output.
J Comp Neurosci 18:151-161

Working code is available from ModelDB
http://senselab.med.yale.edu/modeldb/Sh ... odel=43039

Posted: Thu Jul 19, 2007 6:03 pm
by thats_karlo
Dear Ted,

I looked at the paper and files. It is very nice model.Thanks for this reference. But actually i don't want to model gap junction. I'm wondering is it possible to use gap junction resistance as a coupled resistance between two compartment?

By the way, in one post you suggested:
....put a third section in between the other two, being careful to make the
dimensions and Ra of the intermediate section such that the desired
resistance is obtained; be sure to set that section's cm to 1e-9.
It seems very easy way to create a coupled resistance between to compartment. in this case what is the exact formula for resistance of The third compartment, as you described above? I gusse it should be, something like: R=Ra*L/pi/diam^2

Is it true?

Posted: Sat Jul 21, 2007 8:01 am
by ted
resistance = Ra * path length / cross-sectional area
= Ra * L * 4 / (PI * diam^2)
Don't forget units--Ra is in ohm cm, L and diam in um.

Posted: Sat Jul 21, 2007 10:28 pm
by thats_karlo
Thank you so much for help!